Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 348: 32e

Answer

The braking force on each front wheel is $~~1200~N$

Work Step by Step

In part (c), we found that the normal force on each front wheel is $~~F_N = 3100~N$ We can find the braking force on each front wheel: $F = F_N~\mu_k$ $F = (3100~N)(0.40)$ $F = 1200~N$ The braking force on each front wheel is $~~1200~N$
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