Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 38

Answer

Please see the work below.

Work Step by Step

We know that $F=-\frac{dU}{dr}$ $F=-(\frac{GMm}{r})^{\prime}$ $F=-(GMm)(\frac{1}{r})^{\prime}$ $F=-(GMm)(-\frac{1}{r^2})$ $F=\frac{GMm}{r^2}$
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