Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems - Page 141: 29


Please see the work below.

Work Step by Step

We know that $E=-\frac{GM_{sun}\space M_earth}{2r}$ We plug in the known values to obtain: $E=-\frac{(6.67\times 10^{-11})(1.99\times 10^{30})(5.97\times 10^{24})}{(2)(150\times 10^9)}$ $E=-2.6\times 10^{33}J$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.