Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 29

Answer

Please see the work below.

Work Step by Step

We know that $E=-\frac{GM_{sun}\space M_earth}{2r}$ We plug in the known values to obtain: $E=-\frac{(6.67\times 10^{-11})(1.99\times 10^{30})(5.97\times 10^{24})}{(2)(150\times 10^9)}$ $E=-2.6\times 10^{33}J$
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