Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 37

Answer

$2.73\times10^{-3} m/s^2$

Work Step by Step

a) Recall, $g=\frac{GM}{R^2}$. Using this, we find that the equation for period simplifies to: $ T ^2 = \frac{4\pi^2 R^3}{GM}$ $ \frac{T^2GM}{R^3}=4\pi^2 $ $ \frac{T^2g}{R}=4\pi^2 $ $g=\frac{4\pi^2 R }{T^2}=\frac{4\pi^2 (384400\times10^3) }{(2.36\times10^6)^2}=2.73\times10^{-3} m/s^2$
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