Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems - Page 141: 22

Answer

$T=6513s$

Work Step by Step

We know that: $T=\sqrt{\frac{4\pi^2 r^3}{GM}}$ We plug in the known values to obtain: $T=\sqrt{\frac{4(3.1416)^2(1.737\times 10^6)^3}{(6.67\times 10^{-11})(7.35\times 10^{22})}}$ $T=6513s$
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