Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 18

Answer

$ h = 1.69\times 10^6 \ m$

Work Step by Step

We simplify the equation for the period of a satellite for r to find: $r =\sqrt[3] {\frac{GMT^2}{4\pi^2}}$ Plugging in the value of G, a constant, the mass of the earth, and 7200 seconds for the period (T), we find: $r=8.06\times 10^6$ Subtracting the radius of the earth gives: $ h = 1.69\times 10^6 \ m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.