Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems - Page 141: 34


Please see the work below.

Work Step by Step

We know that $h=\frac{v^2}{2g}$ The above equation shows that height is inversely proportional to g $\implies h_{mars}=(\frac{g_{earth}}{g_{mars}})h_{earth}$ We plug in the known values to obtain: $h_{mars}=(\frac{9.81}{3.74})(2.45)$ $h_{mars}=6.43m$ (b) We know that $\implies h_{moon}=(\frac{g_{earth}}{g_{moon}})h_{earth}$ We plug in the known values to obtain: $h_{moon}=(\frac{9.81}{1.62})(2.45)$ $h_{moon}=14.8m$
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