Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 14

Answer

Please see the work below.

Work Step by Step

We know that $g=\frac{GM}{r^2}$ We plug in the known values to obtain: $g=\frac{6.67\times 10^{-11}(0.330\times 10^{24})}{(2.44\times 10^6)^2}$ $g=3.7\frac{m}{s^2}$ (b) We know that $g=\frac{GM}{r^2}$ We plug in the known values to obtain: $g=\frac{6.67\times 10^{-11}(0.135\times 10^{24})}{(2.58\times 10^6)^2}$ $g=1.4\frac{m}{s^2}$
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