Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 39

Answer

Please see the work below.

Work Step by Step

We know that $T=2\pi\sqrt{\frac{r^3}{GM_m}}$ Where $r=R_m+130000m=1737400+130000=1867400m$ We plug in the known values to obtain: $T=2\pi\sqrt{\frac{(1867400)^3}{(6.67\times 10^{-11})(7.36\times 10^{22})}}=120.60\space minutes$ The time period while the astronaut was cut off$=\frac{T}{2}=60.3\space minutes$
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