## Essential University Physics: Volume 1 (3rd Edition)

We use the equation for escape velocity to obtain: $v_{esc}=\sqrt{\frac{2GM}{R}}$ $v_{esc}=\sqrt{\frac{2(6.67\times10^{-11})(5.98\times10^{24})}{6,371,000}}\approx \fbox { 12 kilometers per second}$ This is greater than the escape velocity of the sun, so it will not return to earth's vicinity.