Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Exercises and Problems: 40

Answer

Please see the work below.

Work Step by Step

We know that orbital speed is given as $v=\sqrt{\frac{Gm}{r}}$ We plug in the known values to obtain: $v=\sqrt{\frac{6.67\times 10^{-11}(1.989\times 10^{30})}{6371000}}$ We plug in the known values to obtain: $v=4.56\times 10^6\frac{m}{s}$ Now we can find the time period as $T=2\pi\sqrt{\frac{r^3}{Gm}}$ We plug in the known values to obtain: $T=2\pi\sqrt{\frac{(6371000)^3}{(6.67\times 10^{-11})(1.989\times 10^{30})}}=8.7722s$
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