## Essential University Physics: Volume 1 (3rd Edition)

We find the escape speed: $v_{esc}=\sqrt{\frac{2GM}{r}}$ $v_{esc}=\sqrt{\frac{2(6.67\times10^{-11})(1.99\times10^{30})}{1.87\times10^{12}}}=1.19\times10^4$ Since the Comet is going faster than this, it will not return to the sun's vicinity. Thus, the motion is hyperbolic, not elliptical.