Answer
Hyperbolic
Work Step by Step
We find the escape speed:
$v_{esc}=\sqrt{\frac{2GM}{r}}$
$v_{esc}=\sqrt{\frac{2(6.67\times10^{-11})(1.99\times10^{30})}{1.87\times10^{12}}}=1.19\times10^4$
Since the Comet is going faster than this, it will not return to the sun's vicinity. Thus, the motion is hyperbolic, not elliptical.
