## Essential University Physics: Volume 1 (3rd Edition)

We set the angular frequencies equal to each other to obtain: $.79\sqrt{\frac{k}{\frac{1}{12}ML^2}}=\sqrt{\frac{k}{\frac{1}{12}ML^2+ 2m(L/2)^2}}$ $.79\sqrt{\frac{k}{\frac{1}{12}ML^2}}=\sqrt{\frac{k}{\frac{1}{12}ML^2+ .5mL^2}}$ $M=821 \ kg$