## Essential University Physics: Volume 1 (3rd Edition)

We first must find the period of an oscillation: $T = 2\pi \sqrt{\frac{2L}{3g}}= 2\pi \sqrt{\frac{2(.188)}{3(9.81)}}=.710\ s$ We multiply this by the number of oscillations to find: $t = .710\ s \times 5974 = 4242.72 \ s = \fbox{70.7 minutes}$