Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems - Page 239: 39

Answer

18 meters per second

Work Step by Step

We first find the period: $T = \frac{1}{f}=\frac{1}{.45}=2.22 \ s$ We now find the speed: $ v = \frac{d}{T} = \frac{40}{2.22}=\fbox {18 meters per second.}$
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