Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems - Page 239: 46


The answer is below.

Work Step by Step

We know: $T=2\pi\sqrt{\frac{L}{a}}$ Thus, we find: a) $T=2\pi\sqrt{\frac{L}{g}}$ b) $T=2\pi\sqrt{\frac{L}{\frac{1}{2}g}}=2\pi\sqrt{\frac2{L}{g}}$ c) $T=2\pi\sqrt{\frac{2L}{3g}}$ d) This is the same as dividing by 0, so the period is infinite or undefined (either is correct).
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