## Essential University Physics: Volume 1 (3rd Edition)

We know: $T=2\pi\sqrt{\frac{L}{a}}$ Thus, we find: a) $T=2\pi\sqrt{\frac{L}{g}}$ b) $T=2\pi\sqrt{\frac{L}{\frac{1}{2}g}}=2\pi\sqrt{\frac2{L}{g}}$ c) $T=2\pi\sqrt{\frac{2L}{3g}}$ d) This is the same as dividing by 0, so the period is infinite or undefined (either is correct).