Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems: 48

Answer

$T=0.34s$

Work Step by Step

As we know that $mg=Kx$ This can be rearranged as: $\frac{m}{K}=\frac{x}{g}$ We plug in the known values to obtain: $\frac{m}{K}=\frac{\frac{0.058}{2}}{9.8}=0.002959$ Now we can find the time period as $T=2\pi\sqrt{\frac{m}{K}}$ $\implies T=2(3.1416)\sqrt{0.002959}$ $T=0.34s$
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