Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems - Page 239: 48



Work Step by Step

As we know that $mg=Kx$ This can be rearranged as: $\frac{m}{K}=\frac{x}{g}$ We plug in the known values to obtain: $\frac{m}{K}=\frac{\frac{0.058}{2}}{9.8}=0.002959$ Now we can find the time period as $T=2\pi\sqrt{\frac{m}{K}}$ $\implies T=2(3.1416)\sqrt{0.002959}$ $T=0.34s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.