## Essential University Physics: Volume 1 (3rd Edition)

(a)$K=6.7\times 10^{-5}\frac{N}{m}$ (b)$m=3.4\times 10^{-10}Kg$
(a)We know that $K=\frac{F}{x}$ We plug in the known values to obtain: $K=\frac{1\times 10^{-12}}{15\times 10^{-9}}=6.7\times 10^{-5}\frac{N}{m}$ (b) We can find the mass as follows: $m=\frac{K}{\omega^2}$ $\implies m=\frac{6.667\times 10^{-5}}{2\pi(70)^2}$ $m=3.4\times 10^{-10}Kg$