Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems: 41

Answer

.69 seconds

Work Step by Step

We must find the period of the oscillations: $ T = \frac{2\pi}{\omega}=\frac{2\pi}{\sqrt{\frac{k}{m}}}=\frac{2\pi}{\sqrt{\frac{2.2}{.43}}}=2.78 \ sec $ We know that $\pi/2$ is one quarter of a period, so it follows: $ t = \frac{2.78}{4} = \fbox{.69 seconds}$
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