Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems: 38

Answer

10 percent more: 65.8 percent 10 percent less: 76.4 percent

Work Step by Step

We know the following equation: $A(\omega)=\frac{F_0}{m\sqrt{(\frac{b}{m})^2\omega_0^2+(w_0^2-w_d^2)^2}}$ Plugging in $1.1\omega_0$ into the equation and dividing by 5 (in the original equation) gives: $=\frac{3.29}{5}=\fbox{65.8 percent}$ Plugging in $.9\omega_0$ into the equation and dividing by 5 (in the original equation) gives: $=\frac{3.82}{5}=\fbox{76.4 percent}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.