Answer
$a)$ 88.2 N,
$b)$ 10.5 kg.
Work Step by Step
a). Reaction force to traction =$2m_{1}g=2\times 4.5\times9.8 = 88.2N$
b). value of $m_{2}$ so that the leg is horizontal $= \frac{15g-44.1}{g}=10.5 kg$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 21
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