College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 10


167 N

Work Step by Step

$T=Frsin\theta$ For force to be minimum, $sin\theta$ needs to be maximum i.e. 1 So, $F_{min}=\frac{T}{r}=\frac{25}{0.15}=166.7N\approx167N$
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