College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 9

Answer

$F=5.6\times10^{2} N$

Work Step by Step

$T=Frsin\theta$ or, $18=F\times 0.04\times sin127^{\circ}$ $F=5.6\times10^{2} N$
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