Answer
a). No it is not possible for the lines to be perfectly do not hit or sit on it.
The wires have their own weights concentrated at center of mass mid-way between the wires which will cause it to sag.
b). $Tsin\theta+Tsin\theta=W$, W is weight of the bird.
$2Tsin\theta=W$
$T=\frac{W}{2sin\theta}=\frac{0.25\times10\times15}{2\times15}=1.25N$
Work Step by Step
a). No it is not possible for the lines to be perfectly do not hit or sit on it.
The wires have their own weights concentrated at center of mass mid-way between the wires which will cause it to sag.
b). $Tsin\theta+Tsin\theta=W$, W is weight of the bird.
$2Tsin\theta=W$
$T=\frac{W}{2sin\theta}=\frac{0.25\times10\times15}{2\times15}=1.25N$
