Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 8

0.58

We have, $r=10 cm=0.1m$ $\omega_{0}=0.5 rad/s$ $\omega=1.25 rad/s$ Angular acceleration = $\frac{0.018}{0.1}=0.18 rad/s^{2}$ $\omega^{2}=\omega_{0}^{2}+2a\theta$ or, $1.25^{2}=0.5^{2}+2\times0.18\times\theta$ $\theta=\frac{175}{48}$ rad So, number of revolutions = $\frac{\frac{175}{48}}{2pi}=0.58$