Answer
333.33 N
Work Step by Step
$T=Frsin\theta$
T=25Nm, r=0.15m, $\theta=30^{\circ}$
Thus, $F=\frac{25}{0.15 sin30^{\circ}}=333.33 N$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 11
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