Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 14

a). 83.3 cm b). 62.5 g

a). Net torque about 50 cm is given by = $w_{1}\times25 - w_{2}\times(x-50)=0$ Hence, $100g \times 25 = 75g\times (x-50)$ or, $\times x=83.3cm$ b). $100g\times25 - mg\times (90-50)=2500g-40mg=0$ or, $m=62.5g$