College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 305: 22

Answer

at $\theta=0^{\circ}$, torque = $5gsin0^{\circ} \times 0.4=0 Nm$ at $\theta=30^{\circ}$, torque = $5gsin30^{\circ} \times 0.4=9.8Nm$ at $\theta=60^{\circ}$, torque = $5gsin60^{\circ} \times 0.4=16.974Nm$ at $\theta=90^{\circ}$, torque = $5gsin90^{\circ} \times 0.4=19.6Nm$

Work Step by Step

Radius = 0.4m, m=5 kg. at $\theta=0^{\circ}$, torque = $5gsin0^{\circ} \times 0.4=0 Nm$ at $\theta=30^{\circ}$, torque = $5gsin30^{\circ} \times 0.4=9.8Nm$ at $\theta=60^{\circ}$, torque = $5gsin60^{\circ} \times 0.4=16.974Nm$ at $\theta=90^{\circ}$, torque = $5gsin90^{\circ} \times 0.4=19.6Nm$
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