Answer
at $\theta=0^{\circ}$, torque = $5gsin0^{\circ} \times 0.4=0 Nm$
at $\theta=30^{\circ}$, torque = $5gsin30^{\circ} \times 0.4=9.8Nm$
at $\theta=60^{\circ}$, torque = $5gsin60^{\circ} \times 0.4=16.974Nm$
at $\theta=90^{\circ}$, torque = $5gsin90^{\circ} \times 0.4=19.6Nm$
Work Step by Step
Radius = 0.4m, m=5 kg.
at $\theta=0^{\circ}$, torque = $5gsin0^{\circ} \times 0.4=0 Nm$
at $\theta=30^{\circ}$, torque = $5gsin30^{\circ} \times 0.4=9.8Nm$
at $\theta=60^{\circ}$, torque = $5gsin60^{\circ} \times 0.4=16.974Nm$
at $\theta=90^{\circ}$, torque = $5gsin90^{\circ} \times 0.4=19.6Nm$