College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 14 - Sound - Learning Path Questions and Exercises - Exercises - Page 524: 32

Answer

$P=282.6W$

Work Step by Step

Since, Intensity level is 110 dB, $110=10log\frac{I}{10^{-12}}$ Thus, $I=0.1$ So, $\frac{P}{4\times3.14\times15^{2}}=0.1$ $P=282.6W$
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