College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 14 - Sound - Learning Path Questions and Exercises - Exercises - Page 524: 20

Answer

a). $8.84\times10^{-3}W/m^{2}$ b). $2.21\times10^{-3}W/m^{2}$

Work Step by Step

a). $I=\frac{P}{4\times pi \times R^{2}}=\frac{1 W}{4\times pi \times(3m)^{2}}=8.84\times10^{-3}W/m^{2}$ b). $I=\frac{P}{4\times pi \times R^{2}}=\frac{1 W}{4\times pi \times(6m)^{2}}=2.21\times10^{-3}W/m^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.