College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 14 - Sound - Learning Path Questions and Exercises - Exercises - Page 524: 31

Answer

$2\times10^{-5}W/m^{2}$

Work Step by Step

$60=10log\frac{I}{10^{-12}}$ So, $I=10^{-6}$ This is the intensity of 1 person. If all 20 people talk together, net intensity = $20\times10^{-6} W/m^{2}=2\times10^{-5}W/m^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.