College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 14 - Sound - Learning Path Questions and Exercises - Exercises - Page 524: 28

Answer

$1.1\times10^{-5} W/m^{2}$

Work Step by Step

$beta=10log\frac{I}{I_{0}}$ $I=I_{0}10^{\frac{beta}{10}}$ For intensity level 60dB, $I=I_{0}10^{\frac{60}{10}}=10^{-12}\times10^{6}=10^{-6}$ For intensity level 70dB, $I=I_{0}10^{\frac{70}{10}}=10^{-12}\times10^{7}=10^{-5}$ So, combined intensity =$10^{-6}+10^{-5}=1.1\times10^{-5} W/m^{2}$
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