Answer
$1.1\times10^{-5} W/m^{2}$
Work Step by Step
$beta=10log\frac{I}{I_{0}}$
$I=I_{0}10^{\frac{beta}{10}}$
For intensity level 60dB, $I=I_{0}10^{\frac{60}{10}}=10^{-12}\times10^{6}=10^{-6}$
For intensity level 70dB, $I=I_{0}10^{\frac{70}{10}}=10^{-12}\times10^{7}=10^{-5}$
So, combined intensity =$10^{-6}+10^{-5}=1.1\times10^{-5} W/m^{2}$