College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 14 - Sound - Learning Path Questions and Exercises - Exercises - Page 524: 18

Answer

22.832 m from the wall.

Work Step by Step

$d=25m-15m/s.t$ Now at $T=0$, $v=331+0.6(0)=331m/s$ Thus, $\frac{25m}{331m/s}+\frac{d}{331m/s}=t$ Solving, $t=0.1445s$ and $d=22.832m$
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