Answer
$1.6dB$
Work Step by Step
Intensity is inversely proportional to square of distance.
So,
$\frac{I_{1}}{I_{2}}=\frac{R_{2}^{2}}{R_{1}^{2}}$
Let required intensity be $I$
So, $\frac{I}{160}=\frac{100}{10000}=\frac{1}{100}$
The intensity level 100 m away is $1.6 dB$