Chapter 14 - Sound - Learning Path Questions and Exercises - Exercises - Page 524: 15

a). $0.107m$ b). $1.43\times10^{-4}s$ c). $4.29\times10^{-4}m$

a). Effective depth = $250 \times wavelength=250\times\frac{1500}{3.5\times10^{6}}=0.107m$ b). time lapse for round trip = $\frac{2\times depth}{speed}=\frac{2\times0.107}{1500}=1.43\times10^{-4}s$ c). smallest detectable detail = wavelength =$\frac{1500}{3.5\times10^{6}}=4.29\times10^{-4}m$