Answer
$38.43C^{\circ}$
Work Step by Step
The required temperature can be determined as follows:
We know that
$Q=mc\Delta T$
This can be rearranged as:
$\Delta T=\frac{Q}{mc}$
We plug in the known values to obtain:
$\Delta T=\frac{1500}{250\times 4.184}=\frac{750}{523}=1.43C^{\circ}$
Now the final temperature is given as
$T_f=T_i+1.43$
$\implies T_f=37+1.43=38.43C^{\circ}$
