Answer
$T=19.5C^{\circ}$
Work Step by Step
We can determine the required temperature as follows:
$Q=mc\Delta T$
We plug in the known values to obtain:
$200=0.005\times 920\times (63-T)$
This simplifies to:
$T=19.5C^{\circ}$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 11 - Heat - Learning Path Questions and Exercises - Exercises - Page 412: 8
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