Chapter 11 - Heat - Learning Path Questions and Exercises - Exercises - Page 412: 4

$3824$

We know that the energy required for a day is given as $4\times 10^5\times 24=9.6\times 10^6J$ As $1 cal=4.184J$ $\implies Energy \space content \space of \space a \space Big \space Mac=600\times 4.184=2510.4J$ Thus, the number of Big Macs required $=\frac{9.6\times 10^6}{2510.4}=3824$