Answer
$6270J$
Work Step by Step
We know that
$1 cal=4.18J$
$\implies 1500 cal=1500\times 4.18=6270 J$
Thus, the required daily requirement is $6270J$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 11 - Heat - Learning Path Questions and Exercises - Exercises - Page 412: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
