College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 11 - Heat - Learning Path Questions and Exercises - Exercises - Page 412: 7


a) (1) more heat. More is the specific heat, more heat is needed. As the specific heat of Cu is more than Pb, copper will require more heat than lead. b) $Q_{Cu}-Q_{Pb}=2.1\times10^{4}\,J$

Work Step by Step

b) $Q= cm\Delta T$ Then $Q_{Cu}=390\,J/(kg\,^{\circ}C)\times1.0\,kg\times80^{\circ}C=3.1\times10^{4}\,J$ $Q_{Pb}= 130\,J/(kg\,^{\circ}C)\times1.0\,kg\times80^{\circ}C=1.0\times10^{4}\,J$ $Q_{Cu}-Q_{Pb}=3.1\times10^{4}\,J-1.0\times10^{4}\,J=2.1\times10^{4}\,J$
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