Answer
(a) Mass of Lead is greater than mass of Copper.
(b) $1.2$
Work Step by Step
(a) We kn ow that
$m=\frac{q}{C\Delta T} $
The above equation shows that $m\propto\frac{1} {C\Delta T}$
For Copper $C_{cu}\Delta T_{cu}=0.38\times 5=1.925J/g$
And for Lead $C_{Pb}\Delta T_{Pb}=0.16\times 10=1.6J/g$
As we can see that $C_{Pb}\Delta T_{Pb}\lt C_{Cu}\Delta T_{Cu}$
Therefore $m_{Pb}\gt m_{Cu}$
(b) We know that
$\frac{m_{Pb}}{m_{Cu}}=\frac{C_{Cu}\Delta T_{Cu}}{C_{Pb}\Delta T_{Pb}}$
We plug in the known values to obtain:
$\frac{m_{Pb}}{m_{Cu}}=\frac{1.925J/g}{1.600J/g}=1.2$
