#### Answer

$x=26.$

#### Work Step by Step

We know that for a matrix
\[
\left[\begin{array}{rr}
a & b \\
c &d \\
\end{array} \right]
\]
the determinant, $D=ad-bc.$
Hence here $D=(x+3)\cdot(-4)-(-6)\cdot(x-2)=28\\-4x-12+6x-12=28\\2x-24=28\\2x=52\\x=26.$