Answer
a. There are 11 g in 0.25 mole of cyclopropane.
b. There are 7.1 g in 0.025 mole of Demerol hydrochloride.
Work Step by Step
- Calculate or find the molar mass for the compound:
a. ( 1.008 $\times$ 6 )+ ( 12.01 $\times$ 3 )= 42.08 g/mol
b. ( 35.45 $\times$ 1 )+ ( 1.008 $\times$ 22 )+ ( 12.01 $\times$ 15 )+ ( 14.01 $\times$ 1 )+ ( 16.00 $\times$ 2 )= 283.79 g/mol
- Using the molar mass as a conversion factor, find the mass in g:
a. $$ 0.25 \space mole \times \frac{ 42.08 \space g}{1 \space mole} = 11 \space g$$
b. $$ 0.025 \space mole \times \frac{ 283.79 \space g}{1 \space mole} = 7.1 \space g$$
