General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 7 - Chemical Reactions and Quantities - 7.5 Molar Mass and Calculations - Questions and Problems - Page 259: 7.46

Answer

a. 0.624 mole b. 0.156 mole c. 2.22 moles d. 3.125 moles

Work Step by Step

- Calculate or find the molar mass for the compound: a. ( 40.08 $\times$ 1 )= 40.08 g/mol b. ( 32.06 $\times$ 1 )= 32.06 g/mol c. ( 1.008 $\times$ 2 )+ ( 16.00 $\times$ 1 )= 18.02 g/mol d. ( 16.00 $\times$ 2 )= 32.00 g/mol - Using the molar mass as a conversion factor, find the amount in moles: a. $$ 25.0 \space g \times \frac{1 \space mole}{ 40.08 \space g} = 0.624 \space mole$$ b. $$ 5.00 \space g \times \frac{1 \space mole}{ 32.06 \space g} = 0.156 \space mole$$ c. $$ 40.0 \space g \times \frac{1 \space mole}{ 18.02 \space g} = 2.22 \space moles$$ d. $$ 100.0 \space g \times \frac{1 \space mole}{ 32.00 \space g} = 3.125 \space moles$$
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