## General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

- Calculate or find the molar mass for the compound: a. ( 22.99 $\times$ 1 )+ ( 35.45 $\times$ 1 )= 58.44 g/mol b. ( 22.99 $\times$ 2 )+ ( 16.00 $\times$ 1 )= 61.98 g/mol c. ( 1.008 $\times$ 2 )+ ( 16.00 $\times$ 1 )= 18.02 g/mol d. ( 12.01 $\times$ 1 )+ ( 16.00 $\times$ 2 )= 44.01 g/mol - Using the molar mass as a conversion factor, find the mass in g: a. $$0.500 \space mole \times \frac{ 58.44 \space g}{1 \space mole} = 29.2 \space g$$ b. $$1.75 \space mole \times \frac{ 61.98 \space g}{1 \space mole} = 108 \space g$$ c. $$0.225 \space mole \times \frac{ 18.02 \space g}{1 \space mole} = 4.05 \space g$$ d. $$4.42 \space mole \times \frac{ 44.01 \space g}{1 \space mole} = 195 \space g$$