# Chapter 7 - Chemical Reactions and Quantities - 7.5 Molar Mass and Calculations - Questions and Problems - Page 259: 7.48

a. 1.00 mole b. 0.0265 mole c. 0.0388 mole d. 0.0270 mole

#### Work Step by Step

- Calculate or find the molar mass for the compound: a. ( 4.00 $\times$ 1 )= 4.00 g/mol b. ( 118.7 $\times$ 1 )+ ( 16.0 $\times$ 2 )= 150.7 g/mol c. ( 52.0 $\times$ 1 )+ ( 1.008 $\times$ 3 )+ ( 16.00 $\times$ 3 )= 103.02 g/mol d. ( 40.08 $\times$ 3 )+ ( 14.01 $\times$ 2 )= 148.26 g/mol - Using the molar mass as a conversion factor, find the amount in moles: a. $$4.00 \space g \times \frac{1 \space mole}{ 4.00 \space g} = 1.00 \space mole$$ b. $$4.00 \space g \times \frac{1 \space mole}{ 150.7 \space g} = 0.0265 \space mole$$ c. $$4.00 \space g \times \frac{1 \space mole}{ 103.02 \space g} = 0.0388 \space mole$$ d. $$4.00 \space g \times \frac{1 \space mole}{ 148.26 \space g} = 0.0270 \space mole$$

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