General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 7 - Chemical Reactions and Quantities - 7.5 Molar Mass and Calculations - Questions and Problems - Page 259: 7.47

Answer

a. 1.24 mole b. 0.781 mole c. 0.321 mole d. 0.106 mole

Work Step by Step

- Calculate or find the molar mass for the compound: a. ( 20.18 $\times$ 1 )= 20.18 g/mol b. ( 16.0 $\times$ 2 )= 32.0 g/mol c. ( 26.98 $\times$ 1 )+ ( 1.008 $\times$ 3 )+ ( 16.0 $\times$ 3 )= 78.00 g/mol d. ( 69.72 $\times$ 2 )+ ( 32.06 $\times$ 3 )= 235.62 g/mol - Using the molar mass as a conversion factor, find the amount in moles: a. $$ 25.0 \space g \times \frac{1 \space mole}{ 20.18 \space g} = 1.24 \space mole$$ b. $$ 25.0 \space g \times \frac{1 \space mole}{ 32.0 \space g} = 0.781 \space mole$$ c. $$ 25.0 \space g \times \frac{1 \space mole}{ 78.00 \space g} = 0.321 \space mole$$ d. $$ 25.0 \space g \times \frac{1 \space mole}{ 235.62 \space g} = 0.106 \space mole$$
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