Answer
a. 66.0 g
b. 0.772 mole
c. 21.6 g
Work Step by Step
a. Molar mass: ( 14.01 $\times$ 2 )+ ( 16.00 $\times$ 1 )= 44.02 g/mol
$$ 1.50 \space mole \times \frac{ 44.02 \space g}{1 \space mole} = 66.0 \space g$$
b. $$ 34.0 \space g \times \frac{1 \space mole}{ 44.02 \space g} = 0.772 \space mole$$
c. Each $ N_2O $ has 2 N atoms, thus:$$ 0.772 \space mole \space N_2O \times \frac{ 2 \space moles \ N }{1 \space mole \space N_2O } = 1.54 \space moles \space N $$
Molar mass = 14.01 g/mol
$$ 1.54 \space moles \times \frac{ 14.01 \space g}{1 \space mole} = 21.6 \space g$$
