Answer
a. 190 g
b. 270 g
c. 230. g
d. 44.0 g
Work Step by Step
- Calculate or find the molar mass for the compound:
a. ( 24.31 $\times$ 1 )+ ( 35.45 $\times$ 2 )= 95.21 g/mol
b. ( 1.008 $\times$ 6 )+ ( 12.01 $\times$ 6 )= 78.11 g/mol
c. ( 1.008 $\times$ 6 )+ ( 12.01 $\times$ 2 )+ ( 16.0 $\times$ 1 )= 46.07 g/mol
d. ( 1.008 $\times$ 6 )+ ( 12.01 $\times$ 3 )+ ( 16.0 $\times$ 3 )= 90.08 g/mol
- Using the molar mass as a conversion factor, find the mass in g:
a. $$ 2.0 \space moles \times \frac{ 95.21 \space g}{1 \space mole} = 190 \space g$$
b. $$ 3.5 \space moles \times \frac{ 78.11 \space g}{1 \space mole} = 270 \space g$$
c. $$ 5.00 \space moles \times \frac{ 46.07 \space g}{1 \space mole} = 230. \space g$$
d. $$ 0.488 \space mole \times \frac{ 90.08 \space g}{1 \space mole} = 44.0 \space g$$
