Answer
a. You will need 602 g of $MgSO_4$ to prepare this bath.
b. There are 74.7 g of KI in 0.450 mole of it.
Work Step by Step
- Calculate or find the molar mass for the compound:
a. ( 24.31 $\times$ 1 )+ ( 16.00 $\times$ 4 )+ ( 32.06 $\times$ 1 )= 120.37 g/mol
b. ( 39.098 $\times$ 1 )+ ( 126.9 $\times$ 1 )= 166.0 g/mol
- Using the molar mass as a conversion factor, find the mass in g:
a. $$ 5.00 \space mole \times \frac{ 120.37 \space g}{1 \space mole} = 602 \space g$$
b. $$ 0.450 \space mole \times \frac{ 166.0 \space g}{1 \space mole} = 74.7 \space g$$
